Beam Buckling Load⚠ unverified
Mechanical / Beams · Compute the Euler critical buckling load of a beam-column
Parameters
| Input | Symbol | Unit | Default | Description |
|---|---|---|---|---|
| E | E | Pa | 1.0 | Young's modulus of the material |
| I | I | m**4 | 1.0 | Second moment of area of the section |
| L | L | m | 1.0 | Unbraced length of the member |
| K | K | — | 1.0 | Effective-length factor accounting for end conditions. Default is 1.0 |
| Output | Symbol | Unit | Description |
|---|---|---|---|
| result | Pcr | N | Critical (Euler) buckling load, in newtons (N) |
The science & history
Understanding the Parameters
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Young's modulus $E$ — the material's elastic stiffness. Buckling is resisted by elastic bending stiffness $EI$, so a stiffer material buckles at a higher load — but note buckling does not depend on material strength, only stiffness. A high-strength steel and a mild steel of the same $E$ buckle at the same load.
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Second moment of area $I$ — use the minimum $I$ of the section, because the column buckles about its weakest axis. This is why efficient columns are tubes or wide-flange shapes with similar inertia in both directions, not flat bars.
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Length $L$ — the unbraced length between points held against lateral movement. Its influence is quadratic ($L^2$ in the denominator): halving the unbraced length quadruples the buckling load, which is why intermediate bracing is so effective.
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Effective-length factor $K$ — encodes the end conditions by converting the real length into the length of the equivalent pinned-pinned column (the distance between inflection points of the buckled shape). $K=1$ for pinned–pinned, $0.5$ for fixed–fixed, $0.7$ for fixed–pinned, and $2$ for a cantilever (fixed–free). The product $KL$ is the effective length.
Derivation (Approaching a Proof)
Model a pinned–pinned column of stiffness $EI$ carrying axial load $P$. If it deflects laterally by $v(x)$, the axial load acting through that offset creates an internal bending moment $M = -P v$. Substituting into the Euler–Bernoulli moment–curvature relation $EI\,v'' = M$ gives the governing equation:
$$EI\,\frac{\mathrm{d}^2 v}{\mathrm{d}x^2} + P\,v = 0.$$
This is a linear eigenvalue problem. Its general solution is $v = A\sin(kx) + B\cos(kx)$ with $k = \sqrt{P/EI}$. The pinned end conditions $v(0)=v(L)=0$ force $B = 0$ and require
$$\sin(kL) = 0 \;\Longrightarrow\; kL = n\pi, \quad n = 1, 2, 3, \dots$$
A non-trivial buckled shape needs $n \ge 1$; the lowest (first) critical load is $n=1$:
$$k = \frac{\pi}{L} \;\Longrightarrow\; P_{cr} = EI k^2 = \frac{\pi^2 E I}{L^2}.$$
Different end restraints change the boundary conditions and hence the distance between inflection points; wrapping that into the effective length $KL$ generalises the result to
$$P_{cr} = \frac{\pi^2 E I}{(K L)^2}.$$
The load appears as an eigenvalue — buckling is a bifurcation, where a new (bent) equilibrium shape becomes possible alongside the straight one.
Dimensional check. $[P_{cr}] = \dfrac{\text{Pa}\cdot\text{m}^4}{\text{m}^2} = \dfrac{\text{N/m}^2 \cdot \text{m}^4}{\text{m}^2} = \text{N}$. ✓
History and Development
Leonhard Euler derived the critical load in 1744 as one of the first triumphs of the calculus of variations applied to the elastica. For a century it was distrusted because real columns failed below the Euler load — later understood to be due to inelastic behaviour and imperfections at low slenderness. Engesser and Kármán's tangent/reduced-modulus theories (late 1800s–1900s) extended it to inelastic buckling, and modern codes (AISC, Eurocode) blend Euler buckling with yielding through column curves parameterised by the Column Slenderness Ratio.
Related Concepts: Euler Buckling Load, Column Slenderness Ratio, Rectangular Moment of Inertia, Moment Of Inertia I Beam, Beam Bending Stress
Notes: Valid only in the elastic, slender regime (high slenderness). Short/stocky members yield or buckle inelastically below $P_{cr}$; check the slenderness ratio and use a code column curve. Uses the minimum $I$ and the effective length $KL$.