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Buck Boost Duty⚠ unverified

Electrical / Power Electronics · Compute the duty cycle for an inverting buck-boost converter

Parameters

InputSymbolUnitDefaultDescription
VinVinV1.0Input voltage
VoutVoutV1.0Output voltage, in volts (V) (typically negative for the inverting topology)
OutputSymbolUnitDescription
resultDDuty cycle (dimensionless), in the range 0 to 1. Returns 0.0 when ``Vin + Vout`` is zero

The science & history

Understanding the Parameters

Derivation (Approaching a Proof)

Inductor volt-second balance in steady state: average voltage across the inductor over one period must be zero (else current ramps unboundedly).

$$V_{in}\,D + V_{out}(1-D) = 0 \;\Rightarrow\; V_{out} = -V_{in}\,\frac{D}{1-D}.$$

Taking magnitudes, $|V_{out}| = V_{in}\,D/(1-D)$. Solving for $D$:

$$D = \frac{|V_{out}|}{|V_{in}| + |V_{out}|}.$$

Because the inductor is never a direct input-to-output path, the converter can both step up and step down and inverts polarity — unlike a pure buck or boost.

History

The inverting buck-boost and its isolated cousin (flyback) became standard low-power supply topologies as power MOSFETs matured. The duty-cycle formula is still the first-order design equation before including switch/diode drops and discontinuous conduction.

Related Concepts: Buck Boost Duty Cycle, Buck Converter Duty Cycle, Boost Converter Duty Cycle, Switching Loss, Conduction Loss

Notes: Registry calculator buck-boost-duty (unverified). Ideal continuous-conduction model. Near- duplicate of Buck Boost Duty Cycle (buck-boost-duty-cycle) — same formula, separate cards; Track B may dedupe. Real $D$ is slightly higher to cover conduction drops and losses.

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