Cone Clutch Torque⚠ unverified
Mechanical / Clutches Brakes · Compute the torque capacity of a cone clutch
Parameters
| Input | Symbol | Unit | Default | Description |
|---|---|---|---|---|
| F | F | N | 1.0 | Axial clamping force |
| mu | μ | — | 1.0 | Coefficient of friction between the cone surfaces (dimensionless) |
| R_mean | Rmean | m | 1.0 | Mean friction radius |
| alpha | α | — | 1.0 | Half-cone angle, in degrees |
| Output | Symbol | Unit | Description |
|---|---|---|---|
| result | T | N*m | Torque capacity, in newton-metres (N*m) |
The science & history
Understanding the Parameters
-
Axial force $F$ — the engaging force along the axis. Because of the wedge, the normal force on the cone face is larger, $N = F/\sin\alpha$, so a cone clutch delivers more torque per unit axial force than a flat disk clutch.
-
Half-cone angle $\alpha$ — the wedge parameter. A small $\alpha$ (steep, narrow cone) gives a large $1/\sin\alpha$ and high torque, but the cones wedge together and are hard to separate (risk of grabbing/self-locking if $\alpha$ is too small, roughly $\alpha < \arctan\mu$). A large $\alpha$ approaching 90° makes $\sin\alpha \to 1$ and the cone clutch reduces to a flat disk clutch. Practical cone half-angles are ~8°–15°.
-
Mean radius $R_{mean}$ — the effective friction radius, as for a disk clutch; the friction force $\mu N$ acts there.
Registry note: $\alpha$ is the half-cone angle in degrees, though labelled dimensionless in the registry. Noted in Known Issues.
Derivation (Approaching a Proof)
The axial engaging force $F$ pushes the male cone into the female cone. On the inclined cone face (half- angle $\alpha$ from the axis), resolve the forces. The normal force $N$ on the cone surface has an axial component that must balance $F$:
$$F = N\sin\alpha \;\Longrightarrow\; N = \frac{F}{\sin\alpha}.$$
The cone face is steeper than a flat plate, so the same axial push produces a larger normal force — the wedge amplification $1/\sin\alpha$. The friction force is $\mu N$, acting tangentially at the mean radius $R_{mean}$, giving a torque
$$T = \mu N R_{mean} = \frac{\mu F R_{mean}}{\sin\alpha}.$$
Compared with a flat disk clutch ($T = \mu F R_{mean}$), the cone clutch multiplies torque by $1/\sin\alpha > 1$. The trade-off appears on disengagement: the axial force needed to pull the cones apart against friction is also amplified, and if $\alpha$ is smaller than the friction angle ($\arctan\mu$) the cones self-lock. (The radial pressure distribution follows the same uniform-wear / uniform-pressure choice as a disk clutch, setting $R_{mean}$.)
Dimensional check. $\sin\alpha$ is dimensionless, so $[T] = \text{N}\cdot\text{m}$. ✓
History and Development
Cone clutches were common in early automobiles and remain the basis of the synchronizer in manual transmissions, where small cone rings quickly match shaft speeds before the dog teeth engage. The wedge- amplification analysis is standard in Shigley; the self-locking limit governs the minimum practical cone angle.
Related Concepts: Disk Clutch Torque, Clutch Torque Capacity Uniform Wear, Multiple Disk Clutch, Clutch Facing Pressure, Friction
Notes: Wedge amplification $1/\sin\alpha$ ($\alpha$ = half-cone angle, deg). Small $\alpha$ → high torque but hard to disengage / self-locking if $\alpha < \arctan\mu$. Reduces to a disk clutch as $\alpha \to 90^\circ$.