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Displacement Current⚠ unverified

Physics / Electromagnetics · Compute the Maxwell displacement current from a changing electric field

Parameters

InputSymbolUnitDefaultDescription
dEdEV*m1.0Change
dtdts1.0Time interval over which the field changes
epsilonεF/m8.85e-12Permittivity of the medium, in farads per metre (F/m). Default is 8.85e-12
OutputSymbolUnitDescription
resultIdADisplacement current, in amperes (A). Returns 0.0 when ``dt`` is not positive

The science & history

Understanding the Parameters

Derivation (Approaching a Proof)

In a charging capacitor, conduction current stops in the gap but $Q = \varepsilon A E$ on the plates changes: $I = dQ/dt = \varepsilon A\,dE/dt$. Maxwell identified $\varepsilon A\,dE/dt$ as displacement current equal to the conduction current in the wires. Continuity of total current closes the circuit in Ampere’s law.

History

James Clerk Maxwell introduced displacement current (1860s) to make Ampere’s law consistent with charge conservation and to predict electromagnetic waves.

Related Concepts: Parallel-Plate Capacitance, Induced Emf, Poynting Vector, Magnetic Field Wire

Notes: Registry calculator displacement-current (unverified). Simplified scalar form; confirm whether area is unity in the implementation. Unit caveat: $\Delta E$ label may be wrong (V·m vs V/m).

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