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Elliptical Interaction⚠ unverified

Mechanical / Stress Analysis · Compute the elliptical yield-locus interaction value for a combined stress state

Parameters

InputSymbolUnitDefaultDescription
sigma_xσxPa1.0Normal stress along the x-axis
sigma_yσyPa1.0Normal stress along the y-axis
tauτPa1.0Shear stress
SySyPa1.0Material yield strength
OutputSymbolUnitDescription
resultEIDimensionless elliptical interaction value; yielding is predicted when it reaches 1

The science & history

Understanding the Parameters

Derivation (Approaching a Proof)

The distortion-energy (von Mises) yield criterion in plane stress is

$$\sigma_x^2 - \sigma_x\sigma_y + \sigma_y^2 + 3\tau^2 = S_y^2.$$

Dividing through by $S_y^2$ and taking the square root gives an interaction value that equals 1 at yield. The registry form drops the cross term and writes the remaining pieces with each component over its own allowable, using $S_{sy} = S_y/\sqrt3 = 0.577\,S_y$ for shear:

$$EI = \sqrt{\frac{\sigma_x^2}{S_y^2} + \frac{\sigma_y^2}{S_y^2} + \frac{\tau^2}{(0.577\,S_y)^2}} = \frac{1}{S_y}\sqrt{\sigma_x^2 + \sigma_y^2 + 3\tau^2}.$$

Comparing with the exact criterion, the two match only when $-\sigma_x\sigma_y$ is negligible; the index is a simplified, uncoupled approximation of the elliptical von Mises locus.

Dimensional check. Each ratio $\sigma/S_y$, $\tau/(0.577 S_y)$ is dimensionless (Pa/Pa), so the root-sum-of-squares $EI$ is dimensionless — a utilisation ratio, as required.

History and Development

The elliptical yield locus is the plane-stress signature of the von Mises / distortion-energy criterion (Huber 1904, von Mises 1913): plotting the yield boundary in the $(\sigma_x, \sigma_y)$ plane traces an ellipse, tilted because of the $-\sigma_x\sigma_y$ coupling. Interaction-ratio formulations like this one are common design shortcuts for combined loading; this particular version keeps the elliptical form but drops the tilt, trading rigour for a simpler expression.

Related Concepts: Von Mises Stress, Tresca Stress, Static Failure Theories, Factor of Safety yield, Principal Stresses, Octahedral Shear Stress

Notes: Omits the von Mises $-\sigma_x\sigma_y$ cross term — exact only when that term is small; non-conservative for like-signed biaxial tension. $0.577 = 1/\sqrt3$ (shear yield fraction). $EI = 1$ → yield; $n = 1/EI$. Use Von Mises Stress for rigour.

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