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Failure Rate From Mtbf⚠ unverified

General Calculations / Reliability · Compute failure rate from mean time between failures

Parameters

InputSymbolUnitDefaultDescription
mtbfmtbf1.0Mean time between failures, in time units
OutputSymbolUnitDescription
resultλ_Constant failure rate, in failures per unit time. Returns 0.0 when ``mtbf`` is not positive

The science & history

Understanding the Parameters

Derivation (Approaching a Proof)

The relation is the algebraic inverse of the mean-life result. Under the constant-hazard model the mean time between failures is $\text{MTBF} = 1/\lambda$ (derived by integrating the exponential survival function, Mtbf From Failure Rate). Solving for the rate:

$$\text{MTBF} = \frac{1}{\lambda} \quad\Longrightarrow\quad \lambda = \frac{1}{\text{MTBF}}. \qquad\blacksquare$$

The physical content is the additivity of rates it enables. For $n$ independent series components each with constant rate $\lambda_i$, the system survival is the product $\prod_i e^{-\lambda_i t} = \exp(-\sum_i\lambda_i\,t)$, identifying the system rate as $\lambda_{sys} = \sum_i \lambda_i$ and hence $\text{MTBF}_{sys} = 1/\sum_i\lambda_i$. Working from MTBF back to $\lambda$ is the step that lets component reliabilities be combined.

Dimensional check. MTBF is in hours, so $\lambda = 1/\text{MTBF}$ is in $\text{1/h}$. $\checkmark$

History and Development

Related Concepts: Mtbf From Failure Rate, Exponential Reliability, Availability, Weibull Failure Rate, Bathtub Curve, Hazard Rate Ratio

Notes: Registry calculator failure-rate-from-mtbf (unverified). $\lambda = 1/\text{MTBF}$ — correct as shipped; exact inverse of Mtbf From Failure Rate (reciprocal duplicate pair). Rates add for series systems ($\lambda_{sys}=\sum\lambda_i$); often quoted in FIT ($10^{-9}/\text{h}$). Valid for constant hazard. Registry labels MTBF dimensionless (is a time). Returns $0$ if MTBF $\le0$.

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