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Fatigue Life (cycles)⚠ unverified

Mechanical / Fatigue · Estimated cycles to failure in the finite-life regime

Parameters

InputSymbolUnitDefaultDescription
SaSaPa350000000.0Alternating stress
SeSePa300000000.0Endurance limit
ff0.9Fatigue strength fraction
SutSutPa600000000.0Ultimate strength
OutputSymbolUnitDescription
NNCycles to failure

The science & history

Understanding the Parameters

Derivation (Approaching a Proof)

Basquin observed that in the finite-life region the S-N data plot as a straight line on log–log axes:

$$S_a = a\,N^{\,b} \;\Longleftrightarrow\; \log S_a = \log a + b\log N.$$

Fit the line through its two known endpoints. At $N = 10^3$ cycles the strength is $S_f = f\,S_{ut}$; at $N = 10^6$ cycles it is the endurance limit $S_e$. Substituting both points and solving for the constants:

$$b = -\frac{1}{3}\log_{10}\!\left(\frac{f\,S_{ut}}{S_e}\right), \qquad a = \frac{(f\,S_{ut})^2}{S_e}.$$

(The $\tfrac13$ comes from the three decades between $10^3$ and $10^6$.) Inverting Basquin's law for the life at a given stress:

$$S_a = a\,N^{\,b} \;\Longrightarrow\; N = \left(\frac{S_a}{a}\right)^{1/b}.$$

Dimensional check. $a$ carries stress units ($(f S_{ut})^2/S_e = \text{Pa}^2/\text{Pa} = \text{Pa}$), so $S_a/a$ is dimensionless; raised to the pure-number power $1/b$, $N$ is dimensionless — a cycle count, as required.

History and Development

O.H. Basquin introduced the power-law S-N form in 1910, giving analytic shape to August Wöhler's foundational fatigue curves. The two-point fit between the $10^3$-cycle strength $f S_{ut}$ and the $10^6$-cycle endurance limit is the Shigley construction for the finite-life line. For lives below $\sim10^3$ cycles the elastic Basquin law breaks down and the strain-life (Coffin–Manson) approach takes over — together they span the low- and high-cycle fatigue regimes.

Related Concepts: S-N Curve, S-N Fatigue Life Prediction, Endurance Limit steel, Marin Endurance Limit, Modified Goodman Factor, Fatigue Strength Coefficient

Notes: Constants derived internally: $a=(f S_{ut})^2/S_e$, $b=-\tfrac13\log_{10}(f S_{ut}/S_e)$. For fully-reversed stress — convert a mean-stress case to an equivalent $S_a$ (Goodman) first. Valid $S_e < S_a < f S_{ut}$; below $S_e$ infinite life, below $10^3$ cycles use strain-life.

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