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Filter Order Rolloff⚠ unverified

Electrical / Filters · Compute the asymptotic roll-off rate of a filter

Parameters

InputSymbolUnitDefaultDescription
nn1.0Filter order (number of poles)
OutputSymbolUnitDescription
resultrolloffdB/decadeRoll-off rate, in decibels per decade (dB/decade)

The science & history

Understanding the Parameters

Derivation (Approaching a Proof)

Far above cutoff, an $n$‑pole low‑pass response falls as a power law, $|H(f)| \propto (f/f_c)^{-n}$. Expressed in decibels,

$$|H|_{\text{dB}} = 20\log_{10}|H| = -20\,n\,\log_{10}\!\frac{f}{f_c} + \text{const}.$$

Increasing frequency by one decade ($f \to 10f$) increases $\log_{10}(f/f_c)$ by $1$, so the magnitude drops by $20n$ dB. Hence the slope is $-20n$ dB/decade. Since a decade is $\log_2 10 \approx 3.32$ octaves, the same slope is $-20n/3.32 \approx -6n$ dB/octave.

History

The "20 dB per decade per pole" rule is a direct reading of the Bode magnitude asymptote, from Hendrik Bode's 1930s–40s feedback‑amplifier work at Bell Labs. Bode plots made filter and control‑loop response something you could sketch and reason about by straight‑line asymptotes — one slope per pole or zero.

Related Concepts: Butterworth Cutoff, RC Low-Pass Cutoff, Sallen Key Lowpass

Notes: Registry calculator filter-order-rolloff (unverified). Asymptotic (far‑from‑cutoff) slope; near the corner the actual response is gentler.

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