Power From Force Velocity⚠ unverified
Physics / Mechanics · Compute instantaneous mechanical power from force and velocity
Parameters
| Input | Symbol | Unit | Default | Description |
|---|---|---|---|---|
| force | force | N | 1.0 | Force applied along the direction of motion |
| velocity | velocity | m/s | 1.0 | Velocity of the point of application |
| Output | Symbol | Unit | Description |
|---|---|---|---|
| result | P | W | Instantaneous power, in watts (W) |
The science & history
Understanding the Parameters
- $F$ — only the component parallel to motion does power; static forces with $v = 0$ do zero power.
- $v$ — higher speed at the same force means higher power (and usually higher energy use rate).
- $P$ — $1\,\text{N}\times 1\,\text{m/s} = 1\,\text{W}$.
Derivation (Approaching a Proof)
Work $dW = F\,ds$ for collinear force. Divide by $dt$:
$$P = \frac{dW}{dt} = F\frac{ds}{dt} = F v.$$
Equivalently from Power $P = dW/dt$ and $v = ds/dt$. Rotational analogue: $P = \tau\omega$.
History
$P = Fv$ is the workhorse relation for vehicle tractive effort, cutting forces, and actuator sizing — the mechanical twin of electrical $P = VI$.
Related Concepts: Power, Work Constant Force, Torque, Watt's Law, Motor Power
Notes: Registry calculator power-from-force-velocity (unverified). Collinear $F$ and $v$ only.