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Pressure Altitude✓ verified

Aerospace / Atmosphere · Pressure altitude from static pressure

Parameters

InputSymbolUnitDefaultDescription
PPPa90000.0Static pressure
OutputSymbolUnitDescription
hhpmPressure altitude

The science & history

Understanding the Parameters

Derivation (Approaching a Proof)

Begin with the troposphere pressure law derived in full from hydrostatic balance and the ideal gas law in ISA Pressure:

$$P = P_0\left(\frac{T}{T_0}\right)^{g/(LR)}, \qquad T = T_0 - L h.$$

Substituting the temperature profile expresses pressure directly in altitude:

$$P = P_0\left(\frac{T_0 - Lh}{T_0}\right)^{g/(LR)} = P_0\left(1 - \frac{Lh}{T_0}\right)^{g/(LR)}.$$

Now solve for $h$. Divide by $P_0$:

$$\frac{P}{P_0} = \left(1 - \frac{Lh}{T_0}\right)^{g/(LR)}.$$

Raise both sides to the reciprocal power $LR/g$ to undo the exponent:

$$\left(\frac{P}{P_0}\right)^{LR/g} = 1 - \frac{Lh}{T_0}.$$

Rearrange for $h$:

$$\frac{Lh}{T_0} = 1 - \left(\frac{P}{P_0}\right)^{LR/g} \quad\Longrightarrow\quad h = \frac{T_0}{L}\left(1 - \left(\frac{P}{P_0}\right)^{LR/g}\right).$$

Insert the standard constants. The scale factor is

$$\frac{T_0}{L} = \frac{288.15}{0.0065} = 44{,}330.77\ \text{m},$$

and the exponent is

$$\frac{LR}{g} = \frac{1}{g/(LR)} = \frac{1}{5.2559} = 0.190261,$$

giving the implemented formula (which rounds these to $44{,}330.8$ and $0.190263$):

$$h_p = 44{,}330.8\left(1 - \left(\frac{P}{101325}\right)^{0.190263}\right). \qquad\blacksquare$$

Sanity checks. At $P = P_0 = 101{,}325\ \text{Pa}$ the bracket is $1 - 1 = 0$, so $h_p = 0$ ✓. At $P = 22{,}632\ \text{Pa}$ (the tropopause), $(22632/101325)^{0.190263} = 0.7519$, giving $h_p = 44{,}330.8 \times 0.2481 \approx 11{,}000\ \text{m}$ ✓ — the inversion recovers the tropopause exactly, confirming it is a true inverse of ISA Pressure within the troposphere. Above sea-level pressure ($P > P_0$, as in a deep low-pressure system at sea level, or below sea level) the bracket goes negative and $h_p < 0$ — correctly reporting a negative pressure altitude, which is physical and routine.

Dimensional check. $P/P_0$ is a dimensionless pressure ratio; raising it to any power leaves it dimensionless, so the bracket is dimensionless and $h_p$ carries the units of $T_0/L$: $\text{K}/(\text{K}/\text{m}) = \text{m}$ ✓.

History and Development

Related Concepts: ISA Pressure, ISA Temperature, ISA Density, Density Altitude, Geopotential Altitude, Stratospheric Temperature, Dynamic Pressure, Bernoulli Total Pressure

Notes: Registry latex_equation is the opaque placeholder $h_p = f(P)$ — the real formula is the inverse troposphere power law above; should be corrected. $44{,}330.8\ \text{m} = T_0/L$ (where the linear ISA temperature profile would reach 0 K — a mathematical artefact, not a physical height); exponent $0.190263 = 1/5.2559$. Troposphere inverse only — above 11 km it extrapolates rather than inverting ISA Pressure's isothermal branch, which is correct by definition for altimetry but means it is not this app's own ISA inverse up there. Pressure altitude is an instrument convention, not a true height; separation relies on shared error.

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