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Rlc Bandwidth⚠ unverified

Electrical / Filters · Compute the bandwidth of an RLC resonant circuit

Parameters

InputSymbolUnitDefaultDescription
RR1.0Resistance
LLH1.0Inductance
OutputSymbolUnitDescription
resultBWHzBandwidth, in hertz (Hz)

The science & history

Understanding the Parameters

Derivation (Approaching a Proof)

For series resonance the current magnitude is $|I| = \dfrac{V}{\sqrt{R^2 + X^2}}$ with $X = \omega L - 1/(\omega C)$. The half‑power points occur where the total reactance equals the resistance, $|X| = R$. Solving $\pm R = \omega L - 1/(\omega C)$ for the two roots $\omega_1, \omega_2$ and subtracting gives the angular bandwidth

$$\Delta\omega = \omega_2 - \omega_1 = \frac{R}{L},$$

so in hertz

$$\text{BW} = \frac{\Delta\omega}{2\pi} = \frac{R}{2\pi L}.$$

Dividing the resonant frequency by this recovers the quality factor: $\dfrac{f_0}{\text{BW}} = \dfrac{\omega_0 L}{R} = Q$ (see Q Factor).

History

The half‑power bandwidth and its reciprocal relation to $Q$ became standard language in radio and filter engineering as tuned circuits were characterised by how narrow a band they select — the defining figure of merit for receivers and band‑pass stages.

Related Concepts: Q Factor, Rlc Series Resonant, Resonance Frequency LC Circuit, Damping Ratio

Notes: Registry calculator rlc-bandwidth (unverified; R mislabelled dimensionless — should be ohms).

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