Specific Strength⚠ unverified
Mechanical / Materials · Strength-to-weight ratio (yield strength / density)
Parameters
| Input | Symbol | Unit | Default | Description |
|---|---|---|---|---|
| Sy | Sy | Pa | 250000000.0 | Yield strength |
| rho | ρ | kg/m^3 | 7800.0 | Density |
| Output | Symbol | Unit | Description |
|---|---|---|---|
| ss | Sy/ρ | J/kg | Specific strength |
The science & history
Understanding the Parameters
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Yield strength $S_y$ — the load-carrying capacity per unit area. Using yield (rather than ultimate) makes this a no-permanent-deformation index; swap in $S_{ut}$ for a fracture-limited version.
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Density $\rho$ — the mass penalty per unit volume. It is the denominator because, for a tie of fixed length carrying a fixed load, mass is proportional to $\rho/S_y$ — so maximising $S_y/\rho$ minimises mass.
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The index $M = S_y/\rho$ — a material property independent of the part. Titanium, aluminium, magnesium, and fibre composites often beat steel on this index even though steel is stronger in absolute terms, because their densities are much lower.
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Physical meaning — $S_y/\rho$ equals the length of a uniform bar (in a gravity field $g$, divided by $g$) that could hang under its own weight before yielding at the top: a "self-support length".
Derivation (Approaching a Proof)
Consider a tension tie of length $L$ (fixed by geometry) carrying a load $F$, free to choose its cross-section $A$ and material. The constraint is that it must not yield: $F/A \le S_y$, so the minimum area is $A = F/S_y$. Its mass is
$$m = \rho\,A\,L = \rho\,\frac{F}{S_y}\,L = (F L)\,\frac{\rho}{S_y}.$$
With $F$ and $L$ fixed by the problem, the mass is minimised by minimising $\rho/S_y$, i.e. maximising the material index
$$M = \frac{S_y}{\rho}.$$
This is the simplest Ashby material-index derivation: separate the fixed functional/geometric requirement from the material group, then optimise the material group alone.
Dimensional check. $M = \dfrac{S_y}{\rho} = \dfrac{\text{Pa}}{\text{kg}/\text{m}^3} = \dfrac{\text{N}/\text{m}^2}{\text{kg}/\text{m}^3} = \dfrac{\text{N}\cdot\text{m}}{\text{kg}} = \dfrac{\text{J}}{\text{kg}}$ — energy per unit mass, as the J/kg label states.
History and Development
Specific strength became a headline design metric with aviation and rocketry, where every kilogram carried costs performance. Michael Ashby's materials-selection methodology (1980s) formalised it as one of a family of material indices derived by the objective-plus-constraint optimisation above, plotted on strength–density Ashby Charts where lines of constant $S_y/\rho$ rank candidate materials at a glance.
Related Concepts: Specific Modulus, Material Selection Index Strength, Ashby Chart Index, Ashby Charts, Hardness to Tensile Strength, Material Selection Index Toughness
Notes: Index for a light, strong tie (tension). Uses yield $S_y$ (no permanent set); use $S_{ut}$ for fracture. Maximise $S_y/\rho$ → minimum mass. Duplicate of Material Selection Index Strength ($S_y/\rho$). Different indices apply for beams/plates in bending.