Thermal Protection Thickness⚠ unverified
Aerospace / Reentry · Compute the required thermal-protection-system (TPS) thickness
Parameters
| Input | Symbol | Unit | Default | Description |
|---|---|---|---|---|
| q | q | W/m**2 | 1.0 | Incident heat flux |
| t | t | s | 1.0 | Heating duration |
| k | k | — | 1.0 | Thermal conductivity of the TPS material, in watts per metre kelvin (W/(m.K)) |
| cp | cp | — | 1.0 | Specific heat capacity of the TPS material, in joules per kilogram kelvin (J/(kg.K)) |
| rho | ρ | kg/m**3 | 1.0 | Density of the TPS material |
| T_max | Tmax | K | 1.0 | Maximum allowable temperature |
| Output | Symbol | Unit | Description |
|---|---|---|---|
| result | thickness | m | Required TPS thickness, in metres (m) |
The science & history
Understanding the Parameters
-
Heat load $q\,t$ — the numerator is the total energy delivered per unit area (Reentry Heat Load). More heat load means more material needed to soak it up, so thickness scales linearly with both flux and duration.
-
Volumetric heat capacity $\rho\,c_p$ — the shield's ability to store heat per unit volume per degree. A material that is dense and has high specific heat (or, better, high latent heat via ablation) absorbs more energy per millimetre, so less thickness is needed. This favours heavy heat-sink metals (beryllium, copper) — which is exactly why heat sinks are heavy and were superseded by ablation for high-energy entry (Ablation Rate).
-
Temperature rise $T_{max} - T_0$ — the usable temperature swing, from the initial $\sim 300\,\text{K}$ to the material limit. A material that tolerates a large temperature rise before failing stores more energy per unit mass, needing less thickness. Refractory materials (high $T_{max}$) are prized.
-
The unused conductivity $k$ — a genuine heat-sink model ignores conductivity (it assumes the whole layer heats uniformly). Conductivity matters for the opposite strategy — an insulator (Shuttle tiles) that keeps its back face cool by resisting heat flow rather than storing it — which this formula does not model.
-
The output $\delta$ — the thickness, and hence (via $\rho\delta$) the areal mass of the shield. Heat-shield mass is often $15$–$30\%$ of an entry vehicle, so this number drives the whole vehicle's mass budget.
Derivation (Approaching a Proof)
Model the heat shield as a lumped heat sink: a slab of area $A$, thickness $\delta$, that absorbs the incident heat by warming uniformly, with negligible loss out the back (conservative) and negligible internal temperature gradient (the lumped assumption). The total heat absorbed over the entry, per unit area, is the heat load $q\,t$.
The energy stored in raising the slab from $T_0$ to at most $T_{max}$ is its mass times specific heat times the temperature rise, per unit area:
$$E_{stored} = (\rho\,\delta)\,c_p\,(T_{max} - T_0).$$
Setting the absorbed heat equal to the stored energy at the limiting condition (back face just reaching $T_{max}$):
$$q\,t = \rho\,\delta\,c_p\,(T_{max} - T_0) \quad\Longrightarrow\quad \delta = \frac{q\,t}{\rho\,c_p\,(T_{max} - T_0)}. \qquad\blacksquare$$
This is a conservative lower bound on thickness for a heat sink: it ignores re-radiation from the hot surface (which helps) and conduction gradients (which hurt), and it says nothing about ablative shields (which carry heat away with departing mass, Ablation Rate) or insulative shields (which limit back-face temperature by low conductivity). It is the right first estimate for a solid heat-sink layer.
Dimensional check. $$\left[\frac{q\,t}{\rho\,c_p\,\Delta T}\right] = \frac{(\text{W}/\text{m}^2)(\text{s})}{(\text{kg}/\text{m}^3)(\text{J}/(\text{kg}\cdot\text{K}))(\text{K})} = \frac{\text{J}/\text{m}^2}{\text{J}/\text{m}^3} = \text{m}.\ \checkmark$$
History and Development
-
Three TPS strategies. Thermal protection comes in three flavours: heat sink (store the heat — this formula; Mercury's beryllium shield), ablative (carry it away with eroding mass — Ablation Rate; Apollo, Orion), and insulative/radiative (block it and re-radiate — Shuttle tiles, reinforced carbon–carbon). Each suits a different flux/duration regime.
-
Why heat sinks faded. Heat-sink shields are simple and reusable but heavy — their mass scales with the full heat load, and for high-energy entry that mass is prohibitive. Ablation, which exploits latent heat and boundary-layer blockage, is far lighter and took over for capsules.
-
Reusable insulators. The Space Shuttle's silica tiles inverted the strategy: instead of absorbing heat they resisted its flow (very low conductivity) and re-radiated from a hot surface, keeping the aluminium structure cool and enabling reuse — a model this heat-sink formula does not capture (hence the unused $k$).
Related Concepts: Reentry Heat Load, Stagnation Heat Flux, Ablation Rate, Peak Heating Altitude, Reentry Time, Thermal Stress, Reentry Heat Flux
Notes: Registry calculator thermal-protection-thickness (unverified). Heat-sink TPS model
$\delta = q t/[\rho c_p(T_{max}-300)]$. Unused input $k$ (conductivity — not part of a heat-sink model);
$c_p$ units-label bug (is J/(kg·K)); reference $T_0 = 300\,\text{K}$ hard-coded (defaults give negative
thickness). Conservative lower bound; does not model ablative or insulative TPS. Flagged in Known Issues.