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Ballistic Coefficient⚠ unverified

Aerospace / Reentry · Ballistic coefficient of a reentry body

Parameters

InputSymbolUnitDefaultDescription
mmkg1000.0Mass
CdCd1.2Drag coefficient
AAm^22.0Reference area
OutputSymbolUnitDescription
betaβkg/m^2Ballistic coefficient

The science & history

Understanding the Parameters

Derivation (Approaching a Proof)

The ballistic coefficient emerges naturally from the entry equation of motion. A body descending through the atmosphere feels a drag force (Drag Force)

$$D = \tfrac12\,\rho\,V^2\,C_d\,A,$$

and its deceleration from drag is that force over its mass:

$$a = \frac{D}{m} = \frac{\tfrac12\,\rho\,V^2\,C_d\,A}{m} = \frac{\rho\,V^2}{2}\cdot\frac{C_d A}{m} = \frac{\rho\,V^2}{2\,\beta},$$

where the grouping $\beta \equiv m/(C_d A)$ falls out as the quantity controlling the deceleration. $\blacksquare$

This is why $\beta$ is defined the way it is: it is the combination of vehicle properties that governs how the atmosphere decelerates the body. Everything downstream — the Allen–Eggers velocity profile, the peak deceleration, and the heating — depends on the vehicle only through $\beta$. A high-$\beta$ body needs a denser atmosphere (lower altitude) to produce the same deceleration, so it penetrates deeper before slowing.

Dimensional check. $$\left[\frac{m}{C_d\,A}\right] = \frac{\text{kg}}{(\text{–})\,\text{m}^2} = \frac{\text{kg}}{\text{m}^2}.\ \checkmark$$

History and Development

Related Concepts: Reentry Velocity, Reentry Deceleration, Peak Heating Altitude, Reentry Time, Drag Force, Stagnation Heat Flux, Lift To Drag Reentry

Notes: Registry calculator ballistic-coefficient (unverified). $\beta = m/(C_d A)$ — correct as shipped. High $\beta$ = deep, fast, hard entry; low $\beta$ = high, gentle deceleration. Governs the entire entry trajectory via the deceleration relation $a = \rho V^2/(2\beta)$. Units kg/m².

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