Hand Calculations logo Hand Calculations All help pages ▾

Reentry Velocity⚠ unverified

Aerospace / Reentry · Compute Allen-Eggers ballistic-reentry velocity as a function of altitude

Parameters

InputSymbolUnitDefaultDescription
v0v0m/s1.0Entry (initial) velocity
betaβkg/m**21.0Ballistic coefficient
hhm1.0Altitude at which the velocity is evaluated
HHm7000.0Atmospheric scale height, in metres (m). Default is 7000
rho0ρ0kg/m**31.225Sea-level atmospheric density, in kilograms per cubic metre (kg/m**3). Default is 1.225
gamma_degγdeg90.0Downward flight-path angle, in degrees. Default is 90.0
OutputSymbolUnitDescription
resultVm/sVelocity at altitude ``h``, in metres per second (m/s)

The science & history

Understanding the Parameters

Derivation (Approaching a Proof)

Allen and Eggers made three assumptions: (1) a purely ballistic (non-lifting) entry, (2) an exponential atmosphere $\rho = \rho_0 e^{-h/H}$, and (3) that during the intense deceleration phase, drag dominates gravity and the flight-path angle $\gamma$ stays roughly constant. The equation of motion along the trajectory is then just drag decelerating the vehicle:

$$m\frac{dV}{dt} = -D = -\tfrac12\rho V^2 C_d A = -\frac{\rho V^2}{2}\cdot\frac{m}{\beta} \;\Longrightarrow\; \frac{dV}{dt} = -\frac{\rho V^2}{2\beta}.$$

Convert time to altitude using the geometry $dh = -V\sin\gamma\,dt$ (the vehicle loses altitude at rate $V\sin\gamma$):

$$\frac{dV}{dh} = \frac{dV}{dt}\cdot\frac{dt}{dh} = \frac{-\rho V^2/(2\beta)}{-V\sin\gamma} = \frac{\rho V}{2\beta\sin\gamma}.$$

Separate variables and substitute $\rho = \rho_0 e^{-h/H}$:

$$\frac{dV}{V} = \frac{\rho_0 e^{-h/H}}{2\beta\sin\gamma}\,dh.$$

Integrate from the entry state ($h \to \infty$, $V = V_0$) down to altitude $h$. The right side integrates to $-\dfrac{\rho_0 H}{2\beta\sin\gamma}e^{-h/H}$, giving

$$\ln\frac{V}{V_0} = -\frac{\rho_0 H}{2\beta\sin\gamma}\,e^{-h/H} \;\Longrightarrow\; V(h) = V_0\,\exp\!\left[-\frac{\rho_0 H}{2\beta\sin\gamma}\,e^{-h/H}\right]. \qquad\blacksquare$$

The nested exponential is exact within the model. Differentiating it yields the deceleration (Reentry Deceleration) and, combined with the heating law, the peak-heating altitude (Peak Heating Altitude) — all in closed form, which is why the Allen–Eggers solution remains the standard first-cut entry analysis.

Dimensional check. The exponent's group $\dfrac{\rho_0 H}{2\beta\sin\gamma} = \dfrac{(\text{kg}/\text{m}^3)(\text{m})}{(\text{kg}/\text{m}^2)} = \text{(–)}$ is dimensionless (as an argument of $\exp$ must be), so $V$ carries the units of $V_0$, m/s. $\checkmark$

History and Development

Related Concepts: Ballistic Coefficient, Reentry Deceleration, Peak Heating Altitude, Reentry Time, Stagnation Heat Flux, Reentry Range, Skip Reentry Delta V, Drag Force

Notes: Registry calculator reentry-velocity (unverified). Allen–Eggers ballistic-entry velocity profile — correct as shipped. Assumes non-lifting entry, exponential atmosphere, constant $\gamma$, drag ≫ gravity. $\gamma$ (gamma_deg) is degrees despite the dimensionless label. Peak deceleration $a_{max}=V_0^2\sin\gamma/(2eH)$ is independent of $\beta$.

← Back to the workspace  ·  All help pages  ·  Getting started