Rivet Shear Stress⚠ unverified
Mechanical / Joints · Average shear stress in a rivet
Parameters
| Input | Symbol | Unit | Default | Description |
|---|---|---|---|---|
| F | F | N | 5000.0 | Shear force |
| d | d | m | 0.01 | Rivet diameter |
| Output | Symbol | Unit | Description |
|---|---|---|---|
| tau | τ | Pa | Shear stress |
The science & history
Understanding the Parameters
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Shear force $F$ — the load carried by one rivet on one shear plane. In a group of rivets sharing a load, divide the total by the rivet count (equal sharing assumes a concentric load; eccentric groups add torsional shear, as for welds).
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Rivet diameter $d$ — for a driven rivet, $d$ is the hole diameter (the rivet upsets to fill it), so the shear area is that of the hole. Shear stress falls as $1/d^2$, so a small diameter increase helps strongly.
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Single vs double shear — the formula is for single shear (one failure plane, area $\pi d^2/4$). In double shear (a central plate between two outers) the rivet is cut on two planes, doubling the resisting area to $2\cdot\pi d^2/4$ and halving the stress — divide $F$ over $2A$.
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Average stress — the real distribution peaks near the plate interface and is not uniform; the average is a design idealisation backed by conservative allowable shear values.
Derivation (Approaching a Proof)
Model the rivet shank as a short cylinder loaded transversely by the two plates. On the shear plane between the plates the two loads form a couple that the shank resists in direct shear. Assuming the shear stress is uniform over the circular cross-section (the standard idealisation), the average stress is simply the force divided by the sheared area:
$$A = \frac{\pi d^2}{4}, \qquad \tau = \frac{F}{A} = \frac{F}{\tfrac{\pi}{4}d^2} = \frac{4F}{\pi d^2}.$$
For $m$ shear planes (e.g. $m = 2$ in double shear) the area becomes $mA$ and $\tau = F/(mA)$. Compare $\tau$ against the rivet's allowable shear ($\approx 0.6\,S_y$ for ductile steel, or a code value) to size the joint.
Dimensional check. $\tau = \dfrac{F}{\tfrac{\pi}{4}d^2} = \dfrac{\text{N}}{\text{m}^2} = \text{Pa}$ — a stress, as required.
History and Development
Rivets were the structural connection of the industrial age — bridges, boilers, ships, and the early skyscrapers were riveted, and the three-check analysis (rivet shear, plate bearing, plate tension) with a joint efficiency ratio is one of the founding applications of strength of materials. Welding and high-strength bolting displaced field riveting through the mid-20th century, but rivet-shear analysis remains standard for aircraft skins (where driven and blind rivets dominate) and legacy-structure assessment.
Related Concepts: Rivet Crushing Stress, Shear Stress, Bolt Tensile Stress Area, Plug Weld Shear, Eccentric Weld Primary Shear
Notes: Single shear (area $\pi d^2/4$); double shear doubles the area, halves $\tau$. $d$ is the hole diameter for driven rivets. Divide the load among rivets in a concentric group. Average (idealised) stress — real distribution is non-uniform.