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Rivet Shear Stress⚠ unverified

Mechanical / Joints · Average shear stress in a rivet

Parameters

InputSymbolUnitDefaultDescription
FFN5000.0Shear force
ddm0.01Rivet diameter
OutputSymbolUnitDescription
tauτPaShear stress

The science & history

Understanding the Parameters

Derivation (Approaching a Proof)

Model the rivet shank as a short cylinder loaded transversely by the two plates. On the shear plane between the plates the two loads form a couple that the shank resists in direct shear. Assuming the shear stress is uniform over the circular cross-section (the standard idealisation), the average stress is simply the force divided by the sheared area:

$$A = \frac{\pi d^2}{4}, \qquad \tau = \frac{F}{A} = \frac{F}{\tfrac{\pi}{4}d^2} = \frac{4F}{\pi d^2}.$$

For $m$ shear planes (e.g. $m = 2$ in double shear) the area becomes $mA$ and $\tau = F/(mA)$. Compare $\tau$ against the rivet's allowable shear ($\approx 0.6\,S_y$ for ductile steel, or a code value) to size the joint.

Dimensional check. $\tau = \dfrac{F}{\tfrac{\pi}{4}d^2} = \dfrac{\text{N}}{\text{m}^2} = \text{Pa}$ — a stress, as required.

History and Development

Rivets were the structural connection of the industrial age — bridges, boilers, ships, and the early skyscrapers were riveted, and the three-check analysis (rivet shear, plate bearing, plate tension) with a joint efficiency ratio is one of the founding applications of strength of materials. Welding and high-strength bolting displaced field riveting through the mid-20th century, but rivet-shear analysis remains standard for aircraft skins (where driven and blind rivets dominate) and legacy-structure assessment.

Related Concepts: Rivet Crushing Stress, Shear Stress, Bolt Tensile Stress Area, Plug Weld Shear, Eccentric Weld Primary Shear

Notes: Single shear (area $\pi d^2/4$); double shear doubles the area, halves $\tau$. $d$ is the hole diameter for driven rivets. Divide the load among rivets in a concentric group. Average (idealised) stress — real distribution is non-uniform.

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