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Temperature Rise⚠ unverified

Electrical / Motors · Compute the steady-state temperature rise of a motor

Parameters

InputSymbolUnitDefaultDescription
P_lossPlossW1.0Dissipated power loss
RthRthK/W1.0Thermal resistance
OutputSymbolUnitDescription
resultΔTKSteady-state temperature rise above ambient, in kelvin (K)

The science & history

Understanding the Parameters

Derivation (Approaching a Proof)

In the thermal–electrical analogy, heat flow $P$ plays the role of current and temperature difference $\Delta T$ the role of voltage, with a thermal resistance $R_{th}$ (K/W) linking them. At steady state all the dissipated power flows out through that resistance, so by the thermal Ohm's law

$$\Delta T = P_{loss}\,R_{th}.$$

This is the equilibrium of the first‑order thermal system whose transient is governed by the Motor Thermal Time Constant $\tau = R_{th}C_{th}$: the temperature climbs exponentially toward $\Delta T$ and reaches $63\%$ of it after one time constant.

History

Lumped thermal‑resistance modelling of electrical machines matured alongside insulation standards (the NEMA/IEC temperature classes A, B, F, H), which cap allowable rise to protect winding insulation and set a motor's continuous rating.

Related Concepts: Motor Thermal Time Constant, Motor Efficiency, RC Time Constant

Notes: Registry calculator temperature-rise (unverified). Single‑node lumped model; real motors have several thermal nodes (winding, iron, frame) with different resistances and capacitances.

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